F1 CARS MYTH

 Before we talk about how to formulate formula 1 cars and how many would be needed to travel in time, we have to first get back to pulley physics classes, seriously, but it's cool. 

       Briefly, the pulley system operates in the following manner, the larger the number of pulleys, the less force required to pull an object attached by these pulleys, rather, simple thus, in a ratio of weight / pulleys. 

       In a simple example, if we had 4 liters of water suspended by 4 sheaves, the force necessary to pull this object of 4kg, considering that 1L = 1kg, would be the force to pull 1kg. 

       But what does pulleys have to do with formula 1 cars and time travel? It's quite simple.

       Imagine that we took 2 Formula 1 cars and welded them in opposite directions, one on top of the other, by their wheels, and we consider that they have traction on all 4 wheels. By analyzing only two connected wheels, we would have the same system of pulleys, but with a differential, in the pulley system, which are drawn by the connecting rope, one end is attached to one surface while the other end is drawn and yet force to pull is reduced and in the case of cars it is as if pulling at both ends then the required force would then be divided by 2 in the case of two cars.

       But this gets even better when we add more cars, if they were 3 cars, the same function of pulleys would be applied but would still be multiplied by 3 because each engine of the car would function like another new tip being pulled into the pulley system, and this is stimulating . 

       Imagine, then, how many formula 1 cars stacked in opposite directions, connected by wheels and welded by the chassis would be needed for the torque, the acceleration, to exceed the speed of light, c?

       Let us consider then. A formula 1 car having 580 horsepower and producing a torque of 0 to 100km / h in 2.6 seconds has an acceleration of 27m / s². So, applying these values ​​to the carriage pulley system, we get an acceleration of 299792458 m / s² how many cars would it take? 

       Well, first let's go back to the equations of the pulleys and then let's formulate the equation of the stacked cars.

       However, when movable pulleys are added to the system, the force required to perform tasks, such as lifting or moving heavy objects, becomes smaller and decreases more and more as we increase the number of pulleys. This system consists of one or more movable pulleys, and a fixed one, is called an exponential carving and its physical principle is relatively simple, see the diagram:

        

       By Newton's second law, we have to equilibrium T + T = P 

       Then 2T = P, then T = P / 2 


       Each mobile pulley decreases weight by half. 

       If we have to lift a weight object "P" and initially apply a tension force "T" on the rope in a system that has "n" movable pulleys, we have the following situation: 

With 1 movable pulley (n = 1) 

T = P / 2 

With 2 mobile pulleys (n = 2) 

T = P / 4 = P / 2 ^ 2 
    
With 3 movable pulleys (n = 3) 

T = P / 8 = P / 2 ^ 3 
          
       We can observe that the exponent of denominator 2 is equal to the number of pulleys n in each situation. Generalizing, we have: 

       An equation to calculate the force "T" for any number of moving pulleys (n). 

T = P / 2 ^ n


But how to apply this to the cars example? 

Well, the acceleration of the car can be compared to the tension of the rope and the torque with weight would be the power of the car. 

For example: 

       A formula 1 car has 580 horses and it has an acceleration that produces a speed that from 0 to 100km \ h does in 2.6 seconds. In other words, its acceleration is a = v / t then (100 / 3.6) / 2.6 = 10m \ s² acceleration and the distance would be 27 meters. 

       So we would have to do a conversion because we want to know its velocity to that the acceleration would be in c, that is, 299792458 m \ s² = 2.6s / (3.6 / xm \ s) we would soon have that x, the velocity, would have to be 2,806,057,406.88 m \ s, that would be his speed in 2.6 seconds with acceleration c.

       But to know how many cars, we apply the power equation. 

P = Fv 

P = Power 
v = speed 
F = Force 

P = F.2.806.057.406,88. 

Only it is a system of sheaves the wheels of the cars and we have the equation of power of the pulleys T = Weight / 2 ^ n 

joining the two equations we have that 

Power = Force.v 

and 

Force = weight / 2 ^ n 

Power = weight / 2 ^ n.velocity 

considering that a car of formula weighs 702 kg 

we have that: 

Power = (weight.qnt of cars / 2 ^ qnt of cars). v 

Power = (702 n / 2 ^ n) 2.806.057.407 

But power is also Work on time 
P = Work / time 
and we have to

Work is force times at a distance 

Work = Strength. distance 

(702 n / 2 ^ n) 2.806.057.407 = work / time 

(702 n / 2 ^ n) 2.806.057.407 = F. distance / time 

only what strength we already have. 

then 

(702 n / 2 Âμm) 2.806.057.407 = (702.n / 2nm). distance / time 

So, for me to know how many cars, just make the intersection 

where: 

v. (702.n / 2nm) = 2.806.057.407. (702 n / 2 n) 

2.806.057.407/(702.n/2 ^ n) = v / (702.n / 


2nm ) 2.806.057.407 = (702 n / 2 nn) 


we then have the following result, where n is the quantity of cars

       But since the problem is not pulleys since each car engine works like an external tip pulling the pulley system, the wheels of the car, and we divide the speed by 2.6 because we want to know the power at t = 0, I believe that this would be the correct formula: 


2.806.057.407/2,6 = (702 n / 2 ^ n) .n 

       We then have:

But, how many cars does it give? 14